A well known fact about joint normally distributed random variables, is that they are independent if and only if their covariance is zero. In one direction, this statement is trivial. *Any* independent pair of random variables has zero covariance (assuming that they are integrable, so that the covariance has a well-defined value). The strength of the statement is in the other direction. Knowing the value of the covariance does not tell us a lot about the joint distribution so, in the case that they are joint normal, the fact that we can determine independence from this is a rather strong statement.

Theorem 1A joint normal pair of random variables are independent if and only if their covariance is zero.

*Proof:* Suppose that *X,Y* are joint normal, such that and , and that their covariance is *c*. Then, the characteristic function of can be computed as

for all . It is standard that the joint characteristic function of a pair of random variables is equal to the product of their characteristic functions if and only if they are independent which, in this case, corresponds to the covariance *c* being zero. ⬜

To demonstrate necessity of the joint normality condition, consider the example from the previous post.

Example 1A pair of standard normal random variablesX,Ywhich have zero covariance, butis not normal.

As their sum is not normal, *X* and *Y* cannot be independent. This example was constructed by setting for some fixed , which is standard normal whenever *X* is. As explained in the previous post, the intermediate value theorem ensures that there is a unique value for *K* making the covariance equal to zero. Continue reading “Independence of Normals”