One of the common themes throughout the theory of continuous-time stochastic processes, is the importance of choosing good versions of processes. Specifying the finite distributions of a process is not sufficient to determine its sample paths so, if a continuous modification exists, then it makes sense to work with that. A relatively straightforward criterion ensuring the existence of a continuous version is provided by Kolmogorov’s continuity theorem.

For any positive real number , a map between metric spaces *E* and *F* is said to be -Hölder continuous if there exists a positive constant *C* satisfying

for all . The smallest value of *C* satisfying this inequality is known as the -Hölder coefficient of . Hölder continuous functions are always continuous and, at least on bounded spaces, is a stronger property for larger values of the coefficient . So, if *E* is a bounded metric space and , then every -Hölder continuous map from *E* is also -Hölder continuous. In particular, 1-Hölder and Lipschitz continuity are equivalent.

Kolmogorov’s theorem gives simple conditions on the pairwise distributions of a process which guarantee the existence of a continuous modification but, also, states that the sample paths are almost surely locally Hölder continuous. That is, they are almost surely Hölder continuous on every bounded interval. To start with, we look at real-valued processes. Throughout this post, we work with repect to a probability space . There is no need to assume the existence of any filtration, since they play no part in the results here

Theorem 1 (Kolmogorov)Letbe a real-valued stochastic process such that there exists positive constantssatisfying

for all. Then, X has a continuous modification which, with probability one, is locally-Hölder continuous for all.

As an example, consider a standard Brownian motion *X*. In this case, is a centred normal variable of variance . Hence,

for a standard normal *N*. Theorem 1 can be applied so long as we take . In that case, and we see that Brownian motion is locally -Hölder continuous for all . By choosing as large as we like, this demonstrates that Brownian motion is locally -Hölder continuous for all . In the other direction, it is not hard to show that it cannot be 1/2-Hölder continuous on any nontrivial interval.

More generally, theorem 1 can be applied to fractional Brownian motion. These are centred Gaussian processes whose finite distributions can be defined by the pairwise covariances. I do not show that these finite distributions are well-defined here (i.e., that the covariance matrix is positive semi-definite). The point is that once we have constructed the finite distributions, Kolmogorov’s theorem ensures the existence of a continuous modification.

Example 1Fractional Brownian motion,, of Hurst parameter H (strictly between 0 and 1), is a centred Gaussian process such thathas standard deviationfor all.

This has a continuous modification which, with probability one, is locally-Hölder continuous for all.

As in the example of standard Brownian motion above, which is actually just fractional Brownian motion with Hurst parameter 1/2, we can compute

and, so, theorem 1 applies with and -Hölder continuity holds for all . Again, letting go to infinity, shows that it holds for all , as claimed. In the reverse direction, it is not difficult to show that the fractional Brownian motion is not *H*-Hölder continuous. So, with increasing value of *H*, the sample paths of fractional brownian motion become smoother, in a sense. This can be seen visually for the paths shown in figure 1 above.

The continuity theorem can be generalised in a couple of ways. Firstly, the process need not be real-valued but, rather, can take values in a complete metric space. Secondly, the (time) index need not be restricted to be the nonnegative reals, but can be allowed to take values in any subset of .

Theorem 2Let E be a separable and complete metric space,, andbe a collection of E-valued random variables. Ifare positive constants satisfying

(1)

for all, thenhas a continuous modification. Furthermore, with probability one, this modification is almost surely-Hölder continuous on all bounded sets for all.

Theorem 1 is just the special case of this result where , and . The proof is given further down. The requirement for the metric space to be *separable*, so that it has a countable dense subset, is only really to ensure that are measurable random variables. I was also a bit unclear in the statement of inequality (1) as to the meaning of the norm on . We could, for example, use the -norm for any , defined by . Alternatively, the norm given by can be used. The fact that these are all equivalent,

means that it does not matter which is used. The only difference is in the value of the arbitrary constant *C*, and does not affect whether the condition of theorem 2 is satisfied.

As an example application of theorem 2, we can construct generalisations of Brownian motion varying over a multidimensional index set. The 2-dimensional case is called a *Brownian sheet*, and a sample is plotted in figure 2 above. This can represent a continuous random path, which itself varies randomly over time. Such processes may be used to build models of interest rates where, at any moment in time, we have an entire yield curve representing the interest rates for all maturities, and these also vary randomly over time.

Lemma 3For each positive integer d, there exists a zero mean Gaussian stochastic processwith covariance

for all. This has a continuous modification, which is locally-Hölder continuous for all.

*Proof:* I make use of the standard result that, for any (real) inner product space *V*, we can define a joint normal collection of random variables , over , with zero mean and such that for all . In fact, joint normal variables can be defined for any positive semidefinite covariance matrix, which applies here since,

Take *V* to be with being the Lebesgue measure. Define,

for all , with denoting the set of all with (). We then have,

as required.

It remains to show that *W* has a modification with the stated Hölder continuity and, for this, it is sufficient to prove the result for index *t* restricted to bounded sets of the form , as the full result will follow by letting *T* increase to infinity. For ,

Hence, for any fixed , there exists a constant *C* satisfying

Theorem 2 can be applied so long as . In this case, we take and see that the continuous modification is -Hölder continuous for all . Letting increase to infinity gives the result. ⬜

#### Proof of the Continuity Theorem

To show that a process is Hölder continuous, we need to bound

In particular, this should be bounded of the form for small . This depends on the joint distribution of as *x* and *y* vary so, if all that we are given to work with is the inequality (1) for the individual distributions, then it is not easy to obtain a good bound. One, rather extreme, upper bound on a set of nonnegative real numbers is given by their sum. This does at least allow us to make use of the linearity of expectation,

In cases of interest, the set *S* will be infinite, and the sum on the right hand side will contain infinitely many terms, so will diverge. As it is, this is not much help. However, if we restrict *x* and *y* to lie on a regular grid whose spacing is of order , this idea does lead to useful bounds. Then, combining with the triangle inequality to split as a finite sum of terms like for pairs lying on such grids, we can obtain reasonable bounds for more general points *x* and *y*. Choosing grids of spacing for integer *n* works well. This leads to considering the restriction of to *dyadic* points where each is of the form for integer *a*. As I stated theorem 2 in a rather general form, where *S* can be any subset of not necessarily including the dyadic points, this adds a slight complication. However, it is easily resolved by approximating the dyadic grid points by elements of *S* instead, and we obtain a proof of Hölder continuity on a dense set of points.

Lemma 4Let E be a separable complete metric space, S be a subset of the unit d-cube, andbe a collection of E-valued random variables satisfying (1).

Then, there exists a countable dense subsetsuch that, with probability one,is-Hölder continuous onfor all. In particular, the-Hölder coefficientsatisfies.

*Proof:* For each nonnegative integer *n*, we let denote the set of dyadic numbers of the form for integer . Also, let be the dyadic interval .

Moving from 1 dimension to *d* dimensions, we let be the collection of such that each is in , and write

We note that, for each *n*, these sets form a partition of . Let denote the set of such that has nonempty intersection with *S* and, for any such *x*, choose . Then, define the finite subset of *S*,

Note that, whatever the choice of , it will lie in for some . Hence, can be chosen to equal and, by doing this, we ensure that . We take . This is easily seen to be dense in *S*. Consider , which will be contained in for some . Then is in and . As *n* can be as large as we like, this shows that is dense.

Consider the random variables,

We note that there are at most possible values of . Then, there are at most possible values for *y* in and, then, . Similarly, if and , then is equal to or 0, for each . Hence, there are at most possible values for *y* and, then, . We suppose that inequality (1) holds using the norm, so that,

Consequently, for , if we set and then,

By the sums of geometric series, these have bounded sum over *n*. For distinct , choose integer with

Also, choose large enough that *x* and *y* are both in . For each integer choose such that and . By construction, and , and similarly for *y*. Furthermore, . Hence, by the triangle inequality,

Hence, the -Hölder coefficient on satisfies,

Raising to the power of gives

which has finite expectation, as required. ⬜

This is the hard part of the proof over with now. Constructing the continuous modification over bounded index sets is straightforward.

Lemma 5Let E be a separable and complete metric space,be bounded, andbe a collection of E-valued random variables satisfying inequality (1). Thenhas a continuous modification. Furthermore, with probability one, this modification is-Hölder continuous for all, and the Hölder coefficient satisfies.

*Proof:* By scaling, if necessary, we can suppose without loss of generality that *S* is contained in the unit *d*-cube . Then, applying lemma 4, there exists a countable dense subset on which, for all , the -Hölder coefficient satisfies . We can let be the event on which for all and, then, choosing any fixed , define the modification,

By uniform continuity, the limit over *y* exists and defines a -Hölder continuous map on *S* with coefficient . It only remains to show that this is indeed a modification. So, choosing and a sequence tending to , Fatou’s lemma gives,

Hence and, so, almost surely. ⬜

Completing the proof by extending to unbounded index sets is now almost a formality.

*Proof of Theorem 2:* For each positive integer *n*, let be the set of with . This is an increasing sequence of bounded subsets of *S*, which eventually contains any given bounded subset. Lemma 5 provides continuous modifications which, furthermore, are -Hölder continuous for each . It is standard that, up to probability one, there can be at most one continuous modification on each set. To be precise, choosing countable dense subsets , the set of all for which over is measurable with probability one. Furthermore, by continuity, and agree on all of , for all . Hence, has probability one and, fixing any , the required global modification is given by

This is clearly -Hölder continuous on any bounded subset of *S*, since it either agrees with for sufficiently large *n* or is constant. ⬜

when we apply Kolmogorov continuity thm, do we require process X_t to be separable?

I’m not sure what you mean by X_t is separable. We do require the metric space in which X takes values to be separable. This is only so that d(X_s,X_t) is a measurable random variable. Even if the metric space is not separable, but you know that these random variables are measurable, then the theorem still works. Even if it is not measurable, so that the probabilities are not even defined, the theorem will still work as long as you interpret the probabilities as outer measures.

Great! Thank you for the explanation!